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Configuration = 80
cycles = (10 5 1 8 3)(9 6 2 7 4)

a = 2, b = 4, c = 6
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cycles = (10 3 1 8 5)(9 6)(7 2)(4)

a = 3, b = 5, c = 10
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cycles = (10)(9)(8)(7 4)(6 3 1)(5 2)

a = 4, b = 5, c = 7
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cycles = (10)(9)(8)(7 2 4)(6)(5 3 1)

a = 2, b = 4, c = 7
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cycles = (10)(9)(8)(7)(6 1 3)(5)(4)(2)